Difference between revisions of "2009 AIME I Problems/Problem 5"
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== Solution == | == Solution == | ||
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== See also == | == See also == | ||
{{AIME box|year=2009|n=I|num-b=4|num-a=6}} | {{AIME box|year=2009|n=I|num-b=4|num-a=6}} | ||
Revision as of 20:52, 20 March 2009
Problem
Triangle 
has 
and 
. Points 
and 
are located on 
and 
respectively so that 
, and 
is the angle bisector of angle 
. Let 
be the point of intersection of 
and , and let 
be the point on line 
for which is the midpoint of 
. If 
, find 
.
Solution
<geogebra>fb9daf193590777e5e9df983e016cc37ed223ec6</geogebra>
See also
| 2009 AIME I (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
