Difference between revisions of "User:Negativebplusorminus"

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which, when read aloud, is "negativebplusorminus..."
 
which, when read aloud, is "negativebplusorminus..."
 
==Signature==
 
==Signature==
Signature as of September 1st, 2011:
+
Signature as of September 1st, 2011:{| class="wikitable" style"border:thin solid gray;background:#eeffe;padding:10px;width:65%"
 +
| style="border:thin solid gray;padding:10px;"|
 +
 
 
<cmath>\sqrt{a+bi}=\sqrt{\frac{a+\sqrt{a^2+b^2}}{2}}+i\sqrt{\frac{-a+\sqrt{a^2+b^2}}{2}}</cmath>Pride goes before destruction, a haughty spirit before a fall.
 
<cmath>\sqrt{a+bi}=\sqrt{\frac{a+\sqrt{a^2+b^2}}{2}}+i\sqrt{\frac{-a+\sqrt{a^2+b^2}}{2}}</cmath>Pride goes before destruction, a haughty spirit before a fall.
 
I swear on my honor that my work and my answers are my own; if I received help, credit is given.
 
I swear on my honor that my work and my answers are my own; if I received help, credit is given.
 +
|}
 
===Equation===
 
===Equation===
 
I derived that equation myself, and I am quite proud of it.  I have a similar one for the fourth roots of <math>a+bi</math> which can be derived from inputting that equation into itself.
 
I derived that equation myself, and I am quite proud of it.  I have a similar one for the fourth roots of <math>a+bi</math> which can be derived from inputting that equation into itself.

Revision as of 10:11, 24 September 2011

A AoPS member.

negativebplusorminus

My username is from the quadratic formula, which states that the roots of the equation $ax^2+bx+c=0$ are \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] which, when read aloud, is "negativebplusorminus..."

Signature

Signature as of September 1st, 2011:{| class="wikitable" style"border:thin solid gray;background:#eeffe;padding:10px;width:65%" | style="border:thin solid gray;padding:10px;"|

\[\sqrt{a+bi}=\sqrt{\frac{a+\sqrt{a^2+b^2}}{2}}+i\sqrt{\frac{-a+\sqrt{a^2+b^2}}{2}}\]Pride goes before destruction, a haughty spirit before a fall. I swear on my honor that my work and my answers are my own; if I received help, credit is given. |}

Equation

I derived that equation myself, and I am quite proud of it. I have a similar one for the fourth roots of $a+bi$ which can be derived from inputting that equation into itself.

Notable Work

Discovered $\sqrt{a+bi}$ in terms of $a$ and $b$, without trigonometry (not even using DeMoivre's theorems), and is noted for using mostly correct punctuation, capitalization, and spelling in the Art of Problem Solving classes (see AoPS Online School for how this classroom operates).

Note that September 21 was one of the last days before AoPS changed the Wiki format.

AoPS Wiki as of September 21, 2011

Statistics

It is Sunday November 3, 2024, 19:09 (GMT).

There have been 233,097 edits to 10,499 articles since January, 2006.

3,273 files have been uploaded.


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Problem of the Day

AoPSWiki:Problem of the Day/September 21, 2011

(View Answer/Add Solution)

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