Difference between revisions of "2004 AMC 12A Problems/Problem 19"
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dot(A);dot(B);dot(C);dot(D);dot(E); | dot(A);dot(B);dot(C);dot(D);dot(E); | ||
− | label("\(D\)", D, | + | label("\(D\)", D,NW); |
label("\(A\)", A,N); | label("\(A\)", A,N); | ||
label("\(B\)", B,W); | label("\(B\)", B,W); | ||
Line 40: | Line 40: | ||
label("\(E\)", E,S); | label("\(E\)", E,S); | ||
label("\(1\)",(-.4,.7)); | label("\(1\)",(-.4,.7)); | ||
− | label("\(1\)",(0,.5), | + | label("\(1\)",(0,0.5),W); |
label("\(r\)", (-.8,-.1)); | label("\(r\)", (-.8,-.1)); | ||
label("\(r\)", (-4/9,-2/3),S); | label("\(r\)", (-4/9,-2/3),S); | ||
− | label("\(h\)", (0,-1/3), | + | label("\(h\)", (0,-1/3), W); |
</asy></center> | </asy></center> | ||
Revision as of 21:52, 26 December 2011
Problem 19
Circles and
are externally tangent to each other, and internally tangent to circle
. Circles
and
are congruent. Circle
has radius
and passes through the center of
. What is the radius of circle
?
![[asy] unitsize(15mm); pair A=(-1,0),B=(2/3,8/9),C=(2/3,-8/9),D=(0,0); draw(Circle(D,2)); draw(Circle(A,1)); draw(Circle(B,8/9)); draw(Circle(C,8/9)); label("\(A\)", A); label("\(B\)", B); label("\(C\)", C); label("D", (-1.2,1.8)); [/asy]](http://latex.artofproblemsolving.com/d/b/0/db04d82b5f5ca4618bfc01360dadf7cd5388f624.png)
Solution
![[asy] unitsize(20mm); pair A=(0,1),B=(-8/9,-2/3),C=(8/9,-2/3),D=(0,0), E=(0,-2/3); draw(Circle(D,2)); draw(Circle(A,1)); draw(Circle(B,8/9)); draw(Circle(C,8/9)); draw(A--B--C--A); draw(B--D--C); draw(A--E); dot(A);dot(B);dot(C);dot(D);dot(E); label("\(D\)", D,NW); label("\(A\)", A,N); label("\(B\)", B,W); label("\(C\)", C,E); label("\(E\)", E,S); label("\(1\)",(-.4,.7)); label("\(1\)",(0,0.5),W); label("\(r\)", (-.8,-.1)); label("\(r\)", (-4/9,-2/3),S); label("\(h\)", (0,-1/3), W); [/asy]](http://latex.artofproblemsolving.com/2/c/9/2c92213020dd5ef1cf8b67ce267ff7503eb45b4b.png)
Note that since
is the center of the larger circle of radius
. Using the Pythagorean Theorem on
,
Now using the Pythagorean Theorem on ,
Substituting ,
See Also
2004 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 18 |
Followed by Problem 20 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |