Difference between revisions of "2012 AMC 12A Problems/Problem 3"
(→See Also) |
(→See Also) |
||
| (One intermediate revision by one other user not shown) | |||
| Line 1: | Line 1: | ||
| − | == Problem | + | == Problem == |
A box <math>2</math> centimeters high, <math>3</math> centimeters wide, and <math>5</math> centimeters long can hold <math>40</math> grams of clay. A second box with twice the height, three times the width, and the same length as the first box can hold <math>n</math> grams of clay. What is <math>n</math>? | A box <math>2</math> centimeters high, <math>3</math> centimeters wide, and <math>5</math> centimeters long can hold <math>40</math> grams of clay. A second box with twice the height, three times the width, and the same length as the first box can hold <math>n</math> grams of clay. What is <math>n</math>? | ||
| Line 10: | Line 10: | ||
{{AMC12 box|year=2012|ab=A|num-b=2|num-a=4}} | {{AMC12 box|year=2012|ab=A|num-b=2|num-a=4}} | ||
| + | {{MAA Notice}} | ||
Revision as of 23:00, 3 July 2013
Problem
A box 
centimeters high, 
centimeters wide, and 
centimeters long can hold 
grams of clay. A second box with twice the height, three times the width, and the same length as the first box can hold 
grams of clay. What is ?
Solution
The first box has volume 
, and the second has volume 
. The second has a volume that is 
times greater, so it holds 
grams.
See Also
| 2012 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 2 |
Followed by Problem 4 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
