Difference between revisions of "2010 AMC 8 Problems/Problem 9"
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Revision as of 00:50, 5 July 2013
Problem
Ryan got of the problems correct on a
-problem test,
on a
-problem test, and
on a
-problem test. What percent of all the problems did Ryan answer correctly?
Solution
Ryan answered problems correct on the first test,
on the second, and
on the third. This amounts to a total of
problems correct. The total number of problems is
Therefore, the percentage is
See Also
2010 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.