Difference between revisions of "1950 AHSME Problems/Problem 13"

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==See Also==
 
==See Also==
  
{{AHSME box|year=1950|num-b=12|num-a=14}}
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{{AHSME 50p box|year=1950|num-b=12|num-a=14}}
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[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Latest revision as of 10:58, 5 July 2013

Problem

The roots of $(x^{2}-3x+2)(x)(x-4)=0$ are:

$\textbf{(A)}\ 4\qquad\textbf{(B)}\ 0\text{ and }4\qquad\textbf{(C)}\ 1\text{ and }2\qquad\textbf{(D)}\ 0,1,2\text{ and }4\qquad\textbf{(E)}\ 1,2\text{ and }4$

Solution

Factor $x^2-3x+2$ to get $(x-2)(x-1).$ The roots are $\boxed{\mathrm{(D)}\ 0,1,2\text{ and }4.}$

See Also

1950 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
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All AHSME Problems and Solutions

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