Difference between revisions of "1950 AHSME Problems/Problem 11"

Revision as of 11:01, 27 May 2014

Problem

If in the formula $C =\frac{en}{R+nr}$ , where $e$ , $n$ , $R$ and $r$ are all positive, $n$ is increased while $e$ , $R$ and $r$ are kept constant, then $C$ :

$\textbf{(A)}\ \text{Increases}\qquad\textbf{(B)}\ \text{Decreases}\qquad\textbf{(C)}\ \text{Remains constant}\qquad\textbf{(D)}\ \text{Increases and then decreases}\qquad\\ \textbf{(E)}\ \text{Decreases and then increases}$

Solution

Divide both the numerator and denominator by $n$ , to get $C=\frac{e}{\frac{R}{n}+r}$ . If $n$ increases then the denominator decreases; so that $C$ $\boxed{\mathrm{(A)}\text{ }\mathrm{ Increases}.}$

1950 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 10	Followed by Problem 12
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All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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 ==Solution==
-Divide both the numerator and denominator by <math>n</math>, to get <math>C=\frac{e}{\frac{R}{n}+r}</math>.  If <math>n</math> increases then the denominator decreases, and so that <math>C</math> <math>\boxed{\mathrm{(A)}\text{ }\mathrm{ Increases}.}</math>
+Divide both the numerator and denominator by <math>n</math>, to get <math>C=\frac{e}{\frac{R}{n}+r}</math>.  If <math>n</math> increases then the denominator decreases; so that <math>C</math> <math>\boxed{\mathrm{(A)}\text{ }\mathrm{ Increases}.}</math>
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Difference between revisions of "1950 AHSME Problems/Problem 11"

Revision as of 11:01, 27 May 2014

Problem

Solution

See Also