Difference between revisions of "2005 CEMC Gauss (Grade 7) Problems/Problem 4"
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| + | == Problem == | ||
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| + | Twelve million added to twelve thousand equals | ||
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| + | <math>\text{(A)}\ 12,012,000 \qquad \text{(B)}\ 12,120,000 \qquad \text{(C)}\ 120,120,000 \qquad \text{(D)}\ 12,000,012,000 \qquad \text{(E)}\ 12,012,000,000</math> | ||
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| + | == Solution == | ||
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Twelve million is written as <math>12,000,000</math> and twelve thousand is written as <math>12,000</math>, so the sum of these two numbers is <math>12,012,000</math>. The answer is <math>A</math>. | Twelve million is written as <math>12,000,000</math> and twelve thousand is written as <math>12,000</math>, so the sum of these two numbers is <math>12,012,000</math>. The answer is <math>A</math>. | ||
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| + | ==See Also== | ||
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| + | {{CEMC box|year=2005|competition=Gauss (Grade 7)|num-b=3|num-a=5}} | ||
Latest revision as of 00:44, 23 October 2014
Problem
Twelve million added to twelve thousand equals
Solution
Twelve million is written as 
and twelve thousand is written as 
, so the sum of these two numbers is 
. The answer is 
.
See Also
| 2005 CEMC Gauss (Grade 7) (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| CEMC Gauss (Grade 7) | ||
