Difference between revisions of "2005 CEMC Gauss (Grade 7) Problems/Problem 4"

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==See Also==
 
==See Also==
  
* [[2005 CEMC Gauss (Grade 7)]]
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{{CEMC box|year=2005|competition=Gauss (Grade 7)|num-b=3|num-a=5}}
* [[2005 CEMC Gauss (Grade 7) Problems]]
 
* [[2005 CEMC Gauss (Grade 7) Problems/Problem 5]]
 

Latest revision as of 00:44, 23 October 2014

Problem

Twelve million added to twelve thousand equals

$\text{(A)}\ 12,012,000 \qquad \text{(B)}\ 12,120,000 \qquad \text{(C)}\ 120,120,000 \qquad \text{(D)}\ 12,000,012,000 \qquad \text{(E)}\ 12,012,000,000$

Solution

Twelve million is written as $12,000,000$ and twelve thousand is written as $12,000$, so the sum of these two numbers is $12,012,000$. The answer is $A$.

See Also

2005 CEMC Gauss (Grade 7) (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
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CEMC Gauss (Grade 7)