Difference between revisions of "2005 CEMC Gauss (Grade 7) Problems/Problem 6"

(Problem 6)
(See Also)
 
(3 intermediate revisions by the same user not shown)
Line 11: Line 11:
 
==See Also==
 
==See Also==
  
[[2005 CEMC Gauss (Grade 7)]]
+
{{CEMC box|year=2005|competition=Gauss (Grade 7)|num-b=5|num-a=7}}

Latest revision as of 00:45, 23 October 2014

Problem

At a class party, each student randomly selects a wrapped prize from a bag. The prizes include books and calculators. There are $27$ prizes in the bag. Meghan is the first to choose a prize. If the probability of Meghan choosing a book for her prize is $2/3$, how many books are in the bag?

$\text{(A)}\ 15 \qquad \text{(B)}\ 9 \qquad \text{(C)}\ 21 \qquad \text{(D)}\ 7 \qquad \text{(E)}\ 18$

Solution

Since Meghan chooses a prize from $27$ in the bag and the probability of her choosing a book is $2/3$, then $2/3$ of the prizes in the bag must be books. Therefore, the number of books in the bag is $(2/3)(27) = 18$. The answer is $E$.

See Also

2005 CEMC Gauss (Grade 7) (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
CEMC Gauss (Grade 7)