Difference between revisions of "2005 CEMC Gauss (Grade 7) Problems/Problem 17"
(Created page with "== Problem == The symbol <math>\begin{array}{|c|c|}\hline 3 & 4 \\ \hline 5 & 6 \\ \hline \end{array}</math> is evaluated as <math>3 \times 6 + 4 \times 5 = 38</math>. If <math...") |
|||
Line 14: | Line 14: | ||
Let the missing number be <math>x</math>. | Let the missing number be <math>x</math>. | ||
− | Using the definition for the evaluation of the symbol, we know that | + | Using the definition for the evaluation of the symbol, we know that <math>2x + 1\times 6 = 16</math> or <math>2x + 6 = 16</math> or <math>2x = 10</math> or <math>x = 5</math>. The answer is <math>E</math>. |
− | 2x + 6 = 16 or 2x = 10 or x = 5. | + | |
+ | == See Also == | ||
+ | |||
+ | {{CEMC box|year=2005|competition=Gauss (Grade 7)|num-b=16|num-a=18}} |
Latest revision as of 10:24, 23 October 2014
Contents
Problem
The symbol is evaluated as . If is evaluated as , what is the number that should be placed in the empty space?
Solution 1
When we calculate the value of the symbol, we add the product of the numbers on each of the two diagonals. The product of the entries on the diagonal with the and the is . Since the symbol is evaluated as , then the product of the entries on the other diagonal is . Since one of the entries on the other diagonal is , then the missing entry must be . The answer is therefore .
Solution 2
Let the missing number be . Using the definition for the evaluation of the symbol, we know that or or or . The answer is .
See Also
2005 CEMC Gauss (Grade 7) (Problems • Answer Key • Resources) | ||
Preceded by Problem 16 |
Followed by Problem 18 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
CEMC Gauss (Grade 7) |