Difference between revisions of "1986 AHSME Problems/Problem 3"
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Revision as of 02:28, 24 October 2014
Problem
is a right angle at
and
. If
(
in
) is the bisector of
, then
Solution
See also
1986 AHSME (Problems • Answer Key • Resources) | ||
Preceded by num-b=2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.