Difference between revisions of "1950 AHSME Problems/Problem 40"
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==Problem== | ==Problem== | ||
| − | The limit of <math> \frac {x^2 | + | The limit of <math> \frac {x^2-1}{x-1}</math> as <math>x</math> approaches <math>1</math> as a limit is: |
<math>\textbf{(A)}\ 0 \qquad | <math>\textbf{(A)}\ 0 \qquad | ||
Revision as of 21:56, 13 March 2015
Problem
The limit of 
as 
approaches 
as a limit is:
Solution
Limits do not take the value of the limiting function at the specified value into account, so we are essentially being asked to find the limit of 
as approaches . This is simply 
.
See Also
| 1950 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 39 |
Followed by Problem 41 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
