Difference between revisions of "2008 AMC 10B Problems/Problem 15"
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So <math>a=3,5,7,9,11,13</math>, and the answer is <math>\boxed{A}</math>. | So <math>a=3,5,7,9,11,13</math>, and the answer is <math>\boxed{A}</math>. | ||
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+ | I love apple pie! | ||
==See also== | ==See also== | ||
{{AMC10 box|year=2008|ab=B|num-b=14|num-a=16}} | {{AMC10 box|year=2008|ab=B|num-b=14|num-a=16}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 21:30, 23 March 2015
Problem
How many right triangles have integer leg lengths and and a hypotenuse of length , where ?
Solution
By the Pythagorean theorem,
This means that .
We know that , and that .
We also know that a must be odd, since the right
side is odd.
So , and the answer is .
I love apple pie!
See also
2008 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.