Difference between revisions of "1998 AJHSME Problems/Problem 13"
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− | ==Problem | + | ==Problem== |
What is the ratio of the area of the shaded square to the area of the large square? (The figure is drawn to scale) | What is the ratio of the area of the shaded square to the area of the large square? (The figure is drawn to scale) | ||
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<math>\text{(A)}\ \dfrac{1}{6} \qquad \text{(B)}\ \dfrac{1}{7} \qquad \text{(C)}\ \dfrac{1}{8} \qquad \text{(D)}\ \dfrac{1}{12} \qquad \text{(E)}\ \dfrac{1}{16}</math> | <math>\text{(A)}\ \dfrac{1}{6} \qquad \text{(B)}\ \dfrac{1}{7} \qquad \text{(C)}\ \dfrac{1}{8} \qquad \text{(D)}\ \dfrac{1}{12} \qquad \text{(E)}\ \dfrac{1}{16}</math> | ||
− | == | + | ==Solutions== |
+ | === Solution 1 === | ||
We can divide the large square into quarters by diagonals. | We can divide the large square into quarters by diagonals. | ||
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<math>\frac{1}{4}\times\frac{1}{2}=\frac{1}{8}=\boxed{C}</math> | <math>\frac{1}{4}\times\frac{1}{2}=\frac{1}{8}=\boxed{C}</math> | ||
+ | === Solution 2 === | ||
+ | Answer: '''C''' | ||
+ | |||
+ | [[File:1998ajhsme-13-2.png]] | ||
+ | |||
+ | Divide the square into 16 smaller squares as shown. The shaded square is formed from 4 half-squares, so its area is 2. The ratio 2 to 16 is 1/8. | ||
== See also == | == See also == | ||
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* [[AJHSME Problems and Solutions]] | * [[AJHSME Problems and Solutions]] | ||
* [[Mathematics competition resources]] | * [[Mathematics competition resources]] | ||
+ | {{MAA Notice}} |
Latest revision as of 23:16, 30 March 2015
Problem
What is the ratio of the area of the shaded square to the area of the large square? (The figure is drawn to scale)
Solutions
Solution 1
We can divide the large square into quarters by diagonals.
Then, in the area of the big square, the little square would have the area.
Solution 2
Answer: C
Divide the square into 16 smaller squares as shown. The shaded square is formed from 4 half-squares, so its area is 2. The ratio 2 to 16 is 1/8.
See also
1998 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.