Difference between revisions of "1950 AHSME Problems/Problem 20"
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By the remainder theorem, the remainder is equal to the expression <math>x^{13}+1</math> when <math>x=1.</math> This gives the answer of <math> \boxed{(\mathrm{D})\ 2.} </math> | By the remainder theorem, the remainder is equal to the expression <math>x^{13}+1</math> when <math>x=1.</math> This gives the answer of <math> \boxed{(\mathrm{D})\ 2.} </math> | ||
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+ | EDIT: This solution is invalid because x can't be 1. | ||
==See Also== | ==See Also== |
Revision as of 10:42, 10 May 2015
Contents
[hide]Problem
When is divided by , the remainder is:
Solution
Solution 1
Use synthetic division, and get that the remainder is
Solution 2
By the remainder theorem, the remainder is equal to the expression when This gives the answer of
EDIT: This solution is invalid because x can't be 1.
See Also
1950 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 19 |
Followed by Problem 21 | |
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All AHSME Problems and Solutions |
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