Difference between revisions of "1986 AHSME Problems/Problem 24"
(Created page with "==Problem== Let <math>p(x) = x^{2} + bx + c</math>, where <math>b</math> and <math>c</math> are integers. If <math>p(x)</math> is a factor of both <math>x^{4} + 6x^{2} + 25</ma...") |
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==Solution== | ==Solution== | ||
+ | p(x) must be a factor of 3(x^4+6x^2+25)-(3x^4+4x^2+28x+5)=14x^2-28x+70=14(x^2-2x+5). Therefore p(x)=x^2 -2x+5 and p(1)=4 | ||
+ | |||
+ | Answer: (D) 4 | ||
== See also == | == See also == |
Revision as of 11:12, 16 June 2015
Problem
Let , where and are integers. If is a factor of both and , what is ?
Solution
p(x) must be a factor of 3(x^4+6x^2+25)-(3x^4+4x^2+28x+5)=14x^2-28x+70=14(x^2-2x+5). Therefore p(x)=x^2 -2x+5 and p(1)=4
Answer: (D) 4
See also
1986 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
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