Difference between revisions of "2014 AMC 10A Problems/Problem 22"
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==Solution 2== | ==Solution 2== | ||
| − | Mark point <math>F</math> on line <math>\overline{CD}</math> such that | + | Mark point <math>F</math> on line <math>\overline{CD}</math> such that <math>\angle EBF = 15&\circ</math>. |
==See Also== | ==See Also== | ||
Revision as of 13:02, 26 December 2015
Contents
Problem
In rectangle 
, 
and 
. Let 
be a point on 
such that 
. What is 
?
Solution
Note that 
. (If you do not know the tangent half-angle formula, it is 
). Therefore, we have 
. Since 
is a 
triangle, 
Solution 2
Mark point 
on line such that $\angle EBF = 15&\circ$ (Error compiling LaTeX. Unknown error_msg).
See Also
| 2014 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 21 |
Followed by Problem 23 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
