Difference between revisions of "2003 AIME I Problems"
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== Problem 1 == | == Problem 1 == | ||
+ | Given that | ||
+ | |||
+ | <center><math> \frac{((3!)!)!}{3!} = k \cdot n!, </math></center> | ||
+ | |||
+ | where <math> k </math> and <math> n </math> are positive integers and <math> n </math> is as large as possible, find <math> k + n. </math> | ||
[[2003 AIME I Problems/Problem 1|Solution]] | [[2003 AIME I Problems/Problem 1|Solution]] | ||
== Problem 2 == | == Problem 2 == | ||
+ | One hundred concentric circles with radii <math> 1, 2, 3, \dots, 100 </math> are drawn in a plane. The interior of the circle of radius 1 is colored red, and each region bounded by consecutive circles is colored either red or green, with no two adjacent regions the same color. The ratio of the total area of the green regions to the area of the circle of radius 100 can be expressed as <math> m/n, </math> where <math> m </math> and <math> n </math> are relatively prime positive integers. Find <math> m + n. </math> | ||
[[2003 AIME I Problems/Problem 2|Solution]] | [[2003 AIME I Problems/Problem 2|Solution]] | ||
== Problem 3 == | == Problem 3 == | ||
+ | Let the set <math> \mathcal{S} = \{8, 5, 1, 13, 34, 3, 21, 2\}. </math> Susan makes a list as follows: for each two-element subset of <math> \mathcal{S}, </math> she writes on her list the greater of the set's two elements. Find the sum of the numbers on the list. | ||
[[2003 AIME I Problems/Problem 3|Solution]] | [[2003 AIME I Problems/Problem 3|Solution]] | ||
== Problem 4 == | == Problem 4 == | ||
+ | Given that <math> \log_{10} \sin x + \log_{10} \cos x = -1 </math> and that <math> \log_{10} (\sin x + \cos x) = \frac{1}{2} (\log_{10} n - 1), </math> find <math> n. </math> | ||
[[2003 AIME I Problems/Problem 4|Solution]] | [[2003 AIME I Problems/Problem 4|Solution]] | ||
== Problem 5 == | == Problem 5 == | ||
+ | Consider the set of points that are inside or within one unit of a rectangular parallelepiped (box) that measures 3 by 4 by 5 units. Given that the volume of this set is <math> (m + n \pi)/p, </math> where <math> m, n, </math> and <math> p </math> are positive integers, and <math> n </math> and <math> p </math> are relatively prime, find <math> m + n + p. </math> | ||
[[2003 AIME I Problems/Problem 5|Solution]] | [[2003 AIME I Problems/Problem 5|Solution]] | ||
== Problem 6 == | == Problem 6 == | ||
+ | The sum of the areas of all triangles whose vertices are also vertices of a 1 by 1 by 1 cube is <math> m + \sqrt{n} + \sqrt{p}, </math> where <math> m, n, </math> and <math> p </math> are integers. Find <math> m + n + p. </math> | ||
[[2003 AIME I Problems/Problem 6|Solution]] | [[2003 AIME I Problems/Problem 6|Solution]] | ||
== Problem 7 == | == Problem 7 == | ||
+ | Point <math> B </math> is on <math> \overline{AC} </math> with <math> AB = 9 </math> and <math> BC = 21. </math> Point <math> D </math> is not on <math> \overline{AC} </math> so that <math> AD = CD, </math> and <math> AD </math> and <math> BD </math> are integers. Let <math> s </math> be the sum of all possible perimeters of <math> \triangle ACD. </math> Find <math> s. </math> | ||
[[2003 AIME I Problems/Problem 7|Solution]] | [[2003 AIME I Problems/Problem 7|Solution]] | ||
== Problem 8 == | == Problem 8 == | ||
+ | In an increasing sequence of four positive integers, the first three terms form an arithmetic progression, the last three terms form a geometric progression, and the first and fourth terms differ by 30. Find the sum of the four terms. | ||
[[2003 AIME I Problems/Problem 8|Solution]] | [[2003 AIME I Problems/Problem 8|Solution]] | ||
== Problem 9 == | == Problem 9 == | ||
+ | An integer between 1000 and 9999, inclusive, is called balanced if the sum of its two leftmost digits equals the sum of its two rightmost digits. How many balanced integers are there? | ||
[[2003 AIME I Problems/Problem 9|Solution]] | [[2003 AIME I Problems/Problem 9|Solution]] | ||
== Problem 10 == | == Problem 10 == | ||
+ | Triangle <math> ABC </math> is isosceles with <math> AC = BC </math> and <math> \angle ACB = 106^\circ. </math> Point <math> M </math> is in the interior of the triangle so that <math> \angle MAC = 7^\circ </math> and <math> \angle MCA = 23^\circ. </math> Find the number of degrees in <math> \angle CMB. </math> | ||
[[2003 AIME I Problems/Problem 10|Solution]] | [[2003 AIME I Problems/Problem 10|Solution]] | ||
== Problem 11 == | == Problem 11 == | ||
+ | An angle <math> x </math> is chosen at random from the interval <math> 0^\circ < x < 90^\circ. </math> Let <math> p </math> be the probability that the numbers <math> \sin^2 x, \cos^2 x, </math> and <math> \sin x \cos x </math> are not the lengths of the sides of a triangle. Given that <math> p = d/n, </math> where <math> d </math> is the number of degrees in <math> \arctan m </math> and <math> m </math> and <math> n </math> are positive integers with <math> m + n < 1000, </math> find <math> m + n. </math> | ||
[[2003 AIME I Problems/Problem 11|Solution]] | [[2003 AIME I Problems/Problem 11|Solution]] | ||
== Problem 12 == | == Problem 12 == | ||
+ | In convex quadrilateral <math> ABCD, \angle A \cong \angle C, AB = CD = 180, </math> and <math> AD \neq BC. </math> The perimeter of <math> ABCD </math> is 640. Find <math> \lfloor 1000 \cos A \rfloor. </math> (The notation <math> \lfloor x \rfloor </math> means the greatest integer that is less than or equal to <math> x. </math>) | ||
[[2003 AIME I Problems/Problem 12|Solution]] | [[2003 AIME I Problems/Problem 12|Solution]] | ||
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== Problem 15 == | == Problem 15 == | ||
In <math> \triangle ABC, AB = 360, BC = 507, </math> and <math> CA = 780. </math> Let <math> M </math> be the midpoint of <math> \overline{CA}, </math> and let <math> D </math> be the point on <math> \overline{CA} </math> such that <math> \overline{BD} </math> bisects angle <math> ABC. </math> Let <math> F </math> be the point on <math> \overline{BC} </math> such that <math> \overline{DF} \perp \overline{BD}. </math> Suppose that <math> \overline{DF} </math> meets <math> \overline{BM} </math> at <math> E. </math> The ratio <math> DE: EF </math> can be written in the form <math> m/n, </math> where <math> m </math> and <math> n </math> are relatively prime positive integers. Find <math> m + n. </math> | In <math> \triangle ABC, AB = 360, BC = 507, </math> and <math> CA = 780. </math> Let <math> M </math> be the midpoint of <math> \overline{CA}, </math> and let <math> D </math> be the point on <math> \overline{CA} </math> such that <math> \overline{BD} </math> bisects angle <math> ABC. </math> Let <math> F </math> be the point on <math> \overline{BC} </math> such that <math> \overline{DF} \perp \overline{BD}. </math> Suppose that <math> \overline{DF} </math> meets <math> \overline{BM} </math> at <math> E. </math> The ratio <math> DE: EF </math> can be written in the form <math> m/n, </math> where <math> m </math> and <math> n </math> are relatively prime positive integers. Find <math> m + n. </math> | ||
+ | |||
[[2003 AIME I Problems/Problem 15|Solution]] | [[2003 AIME I Problems/Problem 15|Solution]] |
Revision as of 16:48, 15 July 2006
Contents
[hide]Problem 1
Given that

where and
are positive integers and
is as large as possible, find
Problem 2
One hundred concentric circles with radii are drawn in a plane. The interior of the circle of radius 1 is colored red, and each region bounded by consecutive circles is colored either red or green, with no two adjacent regions the same color. The ratio of the total area of the green regions to the area of the circle of radius 100 can be expressed as
where
and
are relatively prime positive integers. Find
Problem 3
Let the set Susan makes a list as follows: for each two-element subset of
she writes on her list the greater of the set's two elements. Find the sum of the numbers on the list.
Problem 4
Given that and that
find
Problem 5
Consider the set of points that are inside or within one unit of a rectangular parallelepiped (box) that measures 3 by 4 by 5 units. Given that the volume of this set is where
and
are positive integers, and
and
are relatively prime, find
Problem 6
The sum of the areas of all triangles whose vertices are also vertices of a 1 by 1 by 1 cube is where
and
are integers. Find
Problem 7
Point is on
with
and
Point
is not on
so that
and
and
are integers. Let
be the sum of all possible perimeters of
Find
Problem 8
In an increasing sequence of four positive integers, the first three terms form an arithmetic progression, the last three terms form a geometric progression, and the first and fourth terms differ by 30. Find the sum of the four terms.
Problem 9
An integer between 1000 and 9999, inclusive, is called balanced if the sum of its two leftmost digits equals the sum of its two rightmost digits. How many balanced integers are there?
Problem 10
Triangle is isosceles with
and
Point
is in the interior of the triangle so that
and
Find the number of degrees in
Problem 11
An angle is chosen at random from the interval
Let
be the probability that the numbers
and
are not the lengths of the sides of a triangle. Given that
where
is the number of degrees in
and
and
are positive integers with
find
Problem 12
In convex quadrilateral and
The perimeter of
is 640. Find
(The notation
means the greatest integer that is less than or equal to
)
Problem 13
Let be the number of positive integers that are less than or equal to 2003 and whose base-2 representation has more 1's than 0's. Find the remainder when
is divided by 1000.
Problem 14
The decimal representation of where
and
are relatively prime positive integers and
contains the digits 2, 5, and 1 consecutively, and in that order. Find the smallest value of
for which this is possible.
Problem 15
In and
Let
be the midpoint of
and let
be the point on
such that
bisects angle
Let
be the point on
such that
Suppose that
meets
at
The ratio
can be written in the form
where
and
are relatively prime positive integers. Find