Difference between revisions of "1997 AJHSME Problems/Problem 1"
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− | + | ==Problem== | |
+ | <math>\dfrac{1}{10} + \dfrac{9}{100} + \dfrac{9}{1000} + \dfrac{7}{10000} = </math> | ||
− | < | + | <math>\text{(A)}\ 0.0026 \qquad \text{(B)}\ 0.0197 \qquad \text{(C)}\ 0.1997 \qquad \text{(D)}\ 0.26 \qquad \text{(E)}\ 1.997</math> |
+ | |||
+ | ==Solution== | ||
+ | Convert each fraction to a decimal. | ||
+ | |||
+ | <math>\dfrac{1}{10} + \dfrac{9}{100} + \dfrac{9}{1000} + \dfrac{7}{10000}</math> | ||
+ | |||
+ | <math>0.1+0.09+0.009+0.0007=0.1997</math> | ||
<math>\boxed{\textbf{(C)}}</math> | <math>\boxed{\textbf{(C)}}</math> | ||
+ | |||
+ | == See also == | ||
+ | {{AJHSME box|year=1997|before=1996 AJHSME Last Question|num-a=2}} | ||
+ | * [[AJHSME]] | ||
+ | * [[AJHSME Problems and Solutions]] | ||
+ | * [[Mathematics competition resources]] | ||
+ | {{MAA Notice}} |
Latest revision as of 20:02, 27 October 2016
Problem
Solution
Convert each fraction to a decimal.
See also
1997 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by 1996 AJHSME Last Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.