Difference between revisions of "2006 Cyprus MO/Lyceum/Problem 12"
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==Solution== | ==Solution== | ||
− | \begin{align | + | \begin{align}f(28,17)&=f(11,17)\ &=f(6,11)\ &=f(5,6)\ &=f(1,5)\ |
− | &=f(4,1)\ &=f(3,1)\ &=f(2,1)\ &=f(1,1)\ &=1\ \mathrm{(E)}\end{align | + | &=f(4,1)\ &=f(3,1)\ &=f(2,1)\ &=f(1,1)\ &=1\ \mathrm{(E)}\end{align} |
==See also== | ==See also== |