Difference between revisions of "2017 AMC 10A Problems/Problem 2"
m (→Problem) |
Carpedatdiem (talk | contribs) m (→See Also) |
||
| Line 11: | Line 11: | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2017|ab=A|num-b=1|num-a=3}} | {{AMC10 box|year=2017|ab=A|num-b=1|num-a=3}} | ||
| − | |||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 17:12, 8 March 2017
Problem
Pablo buys popsicles for his friends. The store sells single popsicles for 
each, 
-popsicle boxes for 
each, and 
-popsicle boxes for 
. What is the greatest number of popsicles that Pablo can buy with 
?
Solution
boxes give us the most popsicles/dollar, so we want to buy as many of those as possible. After buying 
, we have left. We cannot buy a third box, so we opt for the box instead (since it has a higher popsicles/dollar ratio than the pack). We're now out of money. We bought 
popsicles, so the answer is 
.
See Also
| 2017 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
