Difference between revisions of "2009 AMC 10B Problems/Problem 10"
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(Note that the resulting triangle is the well-known <math>5-12-13</math> right triangle, scaled by <math>1/5</math>.) | (Note that the resulting triangle is the well-known <math>5-12-13</math> right triangle, scaled by <math>1/5</math>.) | ||
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+ | == Solution #2 == | ||
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+ | A right triangle is formed with the bottom of the flagpole, the snapped part, and the ground. One leg is of length <math>1</math> and the other is length <math>x</math>. By the [[Pythagorean theorem]], we know that <math>\sqrt{x^2+1^2}</math> must be the length of the snapped part of the flagpole. Observe that all the answer choices are rational. If <math>x</math> is rational, <math>5-x</math>, which is the snapped part, must also be rational. Therefore, <math>1, x, 5-x</math> must form a scaled Pythagorean triple. We know that <math>10, 24, 26</math> is a Pythagorean triple, so the corresponding answer must be <math>1, 2.4, 2.6</math>. Adding together the <math>x</math> and the snapped part, this does indeed equal <math>5</math>, so our solution is done. | ||
== See Also == | == See Also == |
Revision as of 21:57, 13 July 2017
Contents
Problem
A flagpole is originally meters tall. A hurricane snaps the flagpole at a point meters above the ground so that the upper part, still attached to the stump, touches the ground meter away from the base. What is ?
Solution
The broken flagpole forms a right triangle with legs and , and hypotenuse . The Pythagorean theorem now states that , hence , and .
(Note that the resulting triangle is the well-known right triangle, scaled by .)
Solution #2
A right triangle is formed with the bottom of the flagpole, the snapped part, and the ground. One leg is of length and the other is length . By the Pythagorean theorem, we know that must be the length of the snapped part of the flagpole. Observe that all the answer choices are rational. If is rational, , which is the snapped part, must also be rational. Therefore, must form a scaled Pythagorean triple. We know that is a Pythagorean triple, so the corresponding answer must be . Adding together the and the snapped part, this does indeed equal , so our solution is done.
See Also
2009 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.