Difference between revisions of "1968 AHSME Problems/Problem 27"
(→Solution) |
m (→See also) |
||
(2 intermediate revisions by one other user not shown) | |||
Line 13: | Line 13: | ||
(These can be found using simple calculations.) | (These can be found using simple calculations.) | ||
Therefore, we know <math>S_{17}+S_{33}+S_{50}</math> =<math>9+17-25</math>, which is <math>\fbox{B}</math>. | Therefore, we know <math>S_{17}+S_{33}+S_{50}</math> =<math>9+17-25</math>, which is <math>\fbox{B}</math>. | ||
+ | |||
+ | |||
Solution By FrostFox | Solution By FrostFox | ||
== See also == | == See also == | ||
− | {{AHSME box|year=1968|num-b=26|num-a=28}} | + | {{AHSME 35p box|year=1968|num-b=26|num-a=28}} |
[[Category: Intermediate Algebra Problems]] | [[Category: Intermediate Algebra Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 00:53, 16 August 2023
Problem
Let , where . Then equals:
Solution
If is even, is negative . If is odd, then is . (These can be found using simple calculations.) Therefore, we know =, which is .
Solution By FrostFox
See also
1968 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 26 |
Followed by Problem 28 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.