Difference between revisions of "1976 AHSME Problems/Problem 3"
(→1976 AHSME Problems) |
Megaboy6679 (talk | contribs) (→Solution) |
||
| (One intermediate revision by one other user not shown) | |||
| Line 7: | Line 7: | ||
==Solution== | ==Solution== | ||
| − | The lengths to the side are <math>1, \sqrt{2^2+1^2}, \sqrt{2^2+1^2}, 1</math>, respectively. Therefore, the sum is <math>2+2\sqrt{5} | + | The lengths to the side are <math>1, \sqrt{2^2+1^2}, \sqrt{2^2+1^2}, 1</math>, respectively. Therefore, the sum is <math>\boxed{\textbf{(E) } 2+2\sqrt{5}}</math>. |
| + | ~MathJams | ||
| + | |||
| + | |||
| + | |||
| + | {{AHSME box|year=1976|before=[[1975 AHSME]]|after=[[1977 AHSME]]}} | ||
Latest revision as of 21:11, 6 February 2023
Problem 3
The sum of the distances from one vertex of a square with sides of length 
to the midpoints of each of the sides of the square is
Solution
The lengths to the side are 
, respectively. Therefore, the sum is 
.
~MathJams
| 1976 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by 1975 AHSME |
Followed by 1977 AHSME | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
