Difference between revisions of "1956 AHSME Problems/Problem 4"
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The man currently earns <math>4000 \cdot \frac{5}{1000} + 3500 \cdot \frac{4}{1000} = 340</math> dollars. So, we need to find the value of <math>x</math> such that | The man currently earns <math>4000 \cdot \frac{5}{1000} + 3500 \cdot \frac{4}{1000} = 340</math> dollars. So, we need to find the value of <math>x</math> such that | ||
<cmath>2500 \cdot \frac{x}{1000} = 160.</cmath> | <cmath>2500 \cdot \frac{x}{1000} = 160.</cmath> | ||
− | Solving, we get <math>x = \boxed{\textbf{(E)} | + | Solving, we get <math>x = \boxed{\textbf{(E) }6.4\%.}</math> |
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==See Also== | ==See Also== |
Latest revision as of 17:11, 14 March 2023
Problem #4
A man has to invest. He invests
at 5% and
at 4%.
In order to have a yearly income of
, he must invest the remainder at:
Solution
The man currently earns dollars. So, we need to find the value of
such that
Solving, we get
See Also
1956 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
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All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.