Difference between revisions of "2010 AMC 8 Problems/Problem 3"
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The highest price was in Month 1, which was \$17. The lowest price was in Month 3, which was \$10. 17 is <math>\frac{17}{10}\cdot100=170\%</math> of 10, and is <math>170-100=70\%</math> more than 10. | The highest price was in Month 1, which was \$17. The lowest price was in Month 3, which was \$10. 17 is <math>\frac{17}{10}\cdot100=170\%</math> of 10, and is <math>170-100=70\%</math> more than 10. | ||
Therefore, the answer is <math> \boxed{\textbf{(C)}\ 70}</math> | Therefore, the answer is <math> \boxed{\textbf{(C)}\ 70}</math> | ||
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+ | ==Video by MathTalks== | ||
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+ | https://youtu.be/EEbksvfujhk | ||
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==See Also== | ==See Also== | ||
{{AMC8 box|year=2010|num-b=2|num-a=4}} | {{AMC8 box|year=2010|num-b=2|num-a=4}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 18:59, 5 February 2023
Problem
The graph shows the price of five gallons of gasoline during the first ten months of the year. By what percent is the highest price more than the lowest price?
Solution
The highest price was in Month 1, which was $17. The lowest price was in Month 3, which was $10. 17 is of 10, and is more than 10. Therefore, the answer is
Video by MathTalks
See Also
2010 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.