Difference between revisions of "2014 AMC 8 Problems/Problem 4"
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<math>\textbf{(A) }85\qquad\textbf{(B) }91\qquad\textbf{(C) }115\qquad\textbf{(D) }133\qquad \textbf{(E) }166</math> | <math>\textbf{(A) }85\qquad\textbf{(B) }91\qquad\textbf{(C) }115\qquad\textbf{(D) }133\qquad \textbf{(E) }166</math> | ||
| − | ==Video Solution | + | ==Solution== |
| + | Since the two prime numbers sum to an odd number, one of them must be even. The only even prime number is <math>2</math>. The other prime number is <math>85-2=83</math>, and the product of these two numbers is <math>83\cdot2=\boxed{\textbf{(E)}~166}</math>. | ||
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| + | ==Video Solution (CREATIVE THINKING)== | ||
| + | https://youtu.be/NW_rCdTO19w | ||
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| + | ~Education, the Study of Everything | ||
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| + | |||
| + | ==Video Solution == | ||
https://youtu.be/6xNkyDgIhEE?t=580 | https://youtu.be/6xNkyDgIhEE?t=580 | ||
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==Video Solution 2== | ==Video Solution 2== | ||
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~savannahsolver | ~savannahsolver | ||
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==See Also== | ==See Also== | ||
{{AMC8 box|year=2014|num-b=3|num-a=5}} | {{AMC8 box|year=2014|num-b=3|num-a=5}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 23:36, 11 December 2023
Contents
Problem
The sum of two prime numbers is 
. What is the product of these two prime numbers?
Solution
Since the two prime numbers sum to an odd number, one of them must be even. The only even prime number is 
. The other prime number is 
, and the product of these two numbers is 
.
Video Solution (CREATIVE THINKING)
~Education, the Study of Everything
Video Solution
https://youtu.be/6xNkyDgIhEE?t=580
Video Solution 2
~savannahsolver
See Also
| 2014 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
