Difference between revisions of "2023 AMC 8 Problems/Problem 12"
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Scrabbler94 (talk | contribs) (not a valid or even recommended solution for an AMC 8) |
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interior. What fraction of the interior of the large white circle is shaded? | interior. What fraction of the interior of the large white circle is shaded? | ||
− | + | <asy> | |
+ | // Diagram by TheMathGuyd | ||
+ | size(6cm); | ||
+ | draw(circle((3,3),3)); | ||
+ | filldraw(circle((2,3),2),lightgrey); | ||
+ | filldraw(circle((3,3),1),white); | ||
+ | filldraw(circle((1,3),1),white); | ||
+ | filldraw(circle((5.5,3),0.5),lightgrey); | ||
+ | filldraw(circle((4.5,4.5),0.5),lightgrey); | ||
+ | filldraw(circle((4.5,1.5),0.5),lightgrey); | ||
+ | int i, j; | ||
+ | for(i=0; i<7; i=i+1) | ||
+ | { | ||
+ | draw((0,i)--(6,i), dashed+grey); | ||
+ | draw((i,0)--(i,6), dashed+grey); | ||
+ | } | ||
+ | </asy> | ||
+ | |||
<math>\textbf{(A)}\ \frac{1}{4} \qquad \textbf{(B)}\ \frac{11}{36} \qquad \textbf{(C)}\ \frac{1}{3} \qquad \textbf{(D)}\ \frac{19}{36} \qquad \textbf{(E)}\ \frac{5}{9}</math> | <math>\textbf{(A)}\ \frac{1}{4} \qquad \textbf{(B)}\ \frac{11}{36} \qquad \textbf{(C)}\ \frac{1}{3} \qquad \textbf{(D)}\ \frac{19}{36} \qquad \textbf{(E)}\ \frac{5}{9}</math> | ||
==Solution 1== | ==Solution 1== | ||
− | First the total area of the <math>3</math> | + | First, the total area of the radius <math>3</math> circle is simply just <math>9\cdot \pi</math> when using our area of a circle formula. |
− | Now from here we have to find our shaded area. This can be done by adding the areas of the | + | Now from here, we have to find our shaded area. This can be done by adding the areas of the <math>\frac{1}{2}</math>-radius circles and add; then, take the area of the <math>1</math> radius circles and subtract that from the area of the <math>2</math> radius circle to get our resulting complex shape area. Adding these up, we will get <math>3\cdot \frac{1}{4} \pi + 4 \pi -\pi - \pi = \frac{3}{4} \pi + 2 \pi = \frac{11\cdot \pi}{4}</math>. |
− | + | So, our answer is <math>\frac {\frac{11}{4} \pi}{9 \pi} = \boxed{\textbf{(B)}\ \frac{11}{36}}</math>. | |
~apex304 | ~apex304 | ||
+ | Minor edits by ~NXC | ||
+ | |||
+ | Minor edits by ~Shriyans Chowdhury | ||
==Solution 2== | ==Solution 2== | ||
− | Pretend each circle is a square. The | + | Pretend each circle is a square. The large shaded circle is a square with area <math>16~\text{units}^2</math>, and the two white circles inside it each have areas of <math>4~\text{units}^2</math>, which adds up to <math>8~\text{units}^2</math>. The three small shaded circles become three squares with area <math>1~\text{units}^2</math>, and add up to <math>3~\text{units}^2</math>. Adding the areas of the shaded circles (19) and subtracting the areas of the white circles (8), we get <math>11~\text{units}^2</math>. Since the largest white circle in which all these other circles are becomes a square that has area <math>36~\text{units}^2</math>, our answer is <math>\boxed{\textbf{(B)}\ \dfrac{11}{36}}</math>. |
+ | |||
+ | -claregu | ||
+ | LaTeX (edits -apex304, CoOlPoTaToEs) | ||
− | - | + | ==Video Solution by Math-X (How to do this question under 30 seconds)== |
+ | https://youtu.be/Ku_c1YHnLt0?si=stUHQ9nHZZE_x-CC&t=1852 ~Math-X | ||
+ | ==Video Solution (Solve under 60 seconds!!!)== | ||
+ | https://youtu.be/6O5UXi-Jwv4?si=KvvABit-3-ZtX7Qa&t=539 | ||
+ | |||
+ | ~hsnacademy | ||
+ | |||
+ | ==Video Solution (HOW TO THINK CREATIVELY!!!) == | ||
+ | https://youtu.be/5wpEBWZjl6o | ||
+ | |||
+ | ~Education the Study of everything | ||
Line 27: | Line 60: | ||
~Star League (https://starleague.us) | ~Star League (https://starleague.us) | ||
+ | |||
+ | ==Video Solution by Magic Square== | ||
+ | https://youtu.be/-N46BeEKaCQ?t=4590 | ||
+ | |||
+ | ==Video Solution by SpreadTheMathLove== | ||
+ | https://www.youtube.com/watch?v=UWoUhV5T92Y | ||
+ | ==Video Solution by Interstigation== | ||
+ | https://youtu.be/DBqko2xATxs&t=1137 | ||
+ | |||
+ | ==Video Solution by harungurcan== | ||
+ | https://www.youtube.com/watch?v=oIGy79w1H8o&t=1154s | ||
+ | |||
+ | ~harungurcan | ||
+ | |||
+ | ==Video Solution by Dr. David== | ||
+ | https://youtu.be/2Ih7F0XHmls | ||
+ | |||
+ | ==Video Solution by WhyMath== | ||
+ | https://youtu.be/ZOi0faHzBR4 | ||
+ | |||
+ | ==See Also== | ||
+ | {{AMC8 box|year=2023|num-b=11|num-a=13}} | ||
+ | {{MAA Notice}} |
Latest revision as of 20:11, 15 December 2024
Contents
[hide]- 1 Problem
- 2 Solution 1
- 3 Solution 2
- 4 Video Solution by Math-X (How to do this question under 30 seconds)
- 5 Video Solution (Solve under 60 seconds!!!)
- 6 Video Solution (HOW TO THINK CREATIVELY!!!)
- 7 Video Solution (Animated)
- 8 Video Solution by Magic Square
- 9 Video Solution by SpreadTheMathLove
- 10 Video Solution by Interstigation
- 11 Video Solution by harungurcan
- 12 Video Solution by Dr. David
- 13 Video Solution by WhyMath
- 14 See Also
Problem
The figure below shows a large white circle with a number of smaller white and shaded circles in its interior. What fraction of the interior of the large white circle is shaded?
Solution 1
First, the total area of the radius circle is simply just when using our area of a circle formula.
Now from here, we have to find our shaded area. This can be done by adding the areas of the -radius circles and add; then, take the area of the radius circles and subtract that from the area of the radius circle to get our resulting complex shape area. Adding these up, we will get .
So, our answer is .
~apex304 Minor edits by ~NXC
Minor edits by ~Shriyans Chowdhury
Solution 2
Pretend each circle is a square. The large shaded circle is a square with area , and the two white circles inside it each have areas of , which adds up to . The three small shaded circles become three squares with area , and add up to . Adding the areas of the shaded circles (19) and subtracting the areas of the white circles (8), we get . Since the largest white circle in which all these other circles are becomes a square that has area , our answer is .
-claregu LaTeX (edits -apex304, CoOlPoTaToEs)
Video Solution by Math-X (How to do this question under 30 seconds)
https://youtu.be/Ku_c1YHnLt0?si=stUHQ9nHZZE_x-CC&t=1852 ~Math-X
Video Solution (Solve under 60 seconds!!!)
https://youtu.be/6O5UXi-Jwv4?si=KvvABit-3-ZtX7Qa&t=539
~hsnacademy
Video Solution (HOW TO THINK CREATIVELY!!!)
~Education the Study of everything
Video Solution (Animated)
~Star League (https://starleague.us)
Video Solution by Magic Square
https://youtu.be/-N46BeEKaCQ?t=4590
Video Solution by SpreadTheMathLove
https://www.youtube.com/watch?v=UWoUhV5T92Y
Video Solution by Interstigation
https://youtu.be/DBqko2xATxs&t=1137
Video Solution by harungurcan
https://www.youtube.com/watch?v=oIGy79w1H8o&t=1154s
~harungurcan
Video Solution by Dr. David
Video Solution by WhyMath
See Also
2023 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.