Difference between revisions of "1995 AHSME Problems/Problem 2"

Latest revision as of 12:58, 5 July 2013

If $\sqrt {2 + \sqrt {x}} = 3$ , then $x =$

$\mathrm{(A) \ 1 } \qquad \mathrm{(B) \ \sqrt{7} } \qquad \mathrm{(C) \ 7 } \qquad \mathrm{(D) \ 49 } \qquad \mathrm{(E) \ 121 }$

$2 + \sqrt{x} = 9 \Longrightarrow \sqrt{x} = 7 \Longrightarrow x = 49 \Rightarrow \mathrm{(D)}$

1995 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions

@@ Line 8: / Line 8: @@
 == See also ==
-{{Old AMC12 box|year=1995|before=First question|num-a=2}}
+{{AHSME box|year=1995|num-b=1|num-a=3}}
 [[Category:Introductory Algebra Problems]]
+{{MAA Notice}}