Difference between revisions of "1995 AHSME Problems/Problem 3"

 
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== Problem ==
 
== Problem ==
The total in-store price for an appliance is <math>\</math><math>99.99</math>. A television commercial advertises the same product for three easy payments of <math>\</math><math>29.98</math> and a one-time shipping and handling charge of <math>\</math><math>9.98</math>. How many cents are saved by buying the appliance from the television advertiser?
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The total in-store price for an appliance is <math>\textdollar 99.99</math>. A television commercial advertises the same product for three easy payments of <math>\textdollar 29.98</math> and a one-time shipping and handling charge of <math>\textdollar 9.98</math>. How many cents are saved by buying the appliance from the television advertiser?
  
 
<math> \mathrm{(A) \ 6 } \qquad \mathrm{(B) \ 7 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 9 } \qquad \mathrm{(E) \ 10 }  </math>
 
<math> \mathrm{(A) \ 6 } \qquad \mathrm{(B) \ 7 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 9 } \qquad \mathrm{(E) \ 10 }  </math>
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== Solution ==
 
== Solution ==
<math>99.99 - (29.98*3 + 9.98) = 99.99 - 99.92 = .07 \Rightarrow \mathrm{(B)}</math>
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IMPORTANT NOTICE: The original problem statement had "how much is saved". However, because this made little sense when the calculations were done, the problem statement was changed to "how many cents".
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We see that 3 payments of <math>\textdollar 29.98</math> will be a total cost of <math>3\cdot(30-.02)=90-.06</math>
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Adding this to <math>\textdollar9.98</math> we have a total of <math>99.98-.06</math>
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Clearly, this differs from <math>\textdollar 99.99</math> by <math>7</math> cents. Thus, the answer is <math>\fbox{\text{(B)}}</math>
  
 
== See also ==
 
== See also ==
{{Old AMC12 box|year=1995|num-b=2|num-a=4}}
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{{AHSME box|year=1995|num-b=2|num-a=4}}
  
 
[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Latest revision as of 12:58, 5 July 2013

Problem

The total in-store price for an appliance is $\textdollar 99.99$. A television commercial advertises the same product for three easy payments of $\textdollar 29.98$ and a one-time shipping and handling charge of $\textdollar 9.98$. How many cents are saved by buying the appliance from the television advertiser?

$\mathrm{(A) \ 6 } \qquad \mathrm{(B) \ 7 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 9 } \qquad \mathrm{(E) \ 10 }$


Solution

IMPORTANT NOTICE: The original problem statement had "how much is saved". However, because this made little sense when the calculations were done, the problem statement was changed to "how many cents".

We see that 3 payments of $\textdollar 29.98$ will be a total cost of $3\cdot(30-.02)=90-.06$

Adding this to $\textdollar9.98$ we have a total of $99.98-.06$

Clearly, this differs from $\textdollar 99.99$ by $7$ cents. Thus, the answer is $\fbox{\text{(B)}}$

See also

1995 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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