Difference between revisions of "2004 AMC 12A Problems/Problem 5"
(New page: ==Problem== The graph of the line <math>y=mx+b</math> is shown. Which of the following is true? Image:2004 AMC 12A Problem 5.png <math>\mathrm {(A)} mb<-1 \qquad \mathrm {(B)} -1<mb<...) |
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[[Image:2004 AMC 12A Problem 5.png]] | [[Image:2004 AMC 12A Problem 5.png]] | ||
| − | <math>\mathrm {(A)} mb<-1 \qquad \mathrm {(B)} -1<mb<0 \qquad \mathrm {(C)} mb=0 \qquad \mathrm {(D)} 0<mb<1 \qquad \mathrm {(E)} mb>1</math> | + | <math>\mathrm {(A)} mb<-1 \qquad \mathrm {(B)} -1<mb<0 \qquad \mathrm {(C)} mb=0 \qquad \mathrm {(D)}</math> <math> 0<mb<1 \qquad \mathrm {(E)} mb>1</math> |
==Solution== | ==Solution== | ||
| − | + | The line appears to have a slope of <math>-\dfrac{1}{2}</math> and y-intercept of <math>\dfrac{4}{5}</math> up. | |
| + | |||
| + | <math>\dfrac{4}{5}\cdot \dfrac{-1}{2}=\dfrac{-4}{10} \Rightarrow \mathrm {(B)}</math> | ||
==See also== | ==See also== | ||
| + | {{AMC12 box|year=2004|ab=A|num-b=4|num-a=6}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 14:48, 12 July 2017
Problem
The graph of the line 
is shown. Which of the following is true?
Solution
The line appears to have a slope of 
and y-intercept of 
up.
See also
| 2004 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 4 |
Followed by Problem 6 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
