Difference between revisions of "2001 AMC 8 Problems/Problem 1"

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==Problem==
 
==Problem==
Casey's shop class is making a golf trophy. He has to paint 300 dimples on a golf ball. If it takes him 2 seconds to paint one dimple, how many minutes will he need to do his job?
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Casey's shop class is making a golf trophy. He has to paint 300 dimples on a golf ball. If it takes him 2 seconds to paint one dimple, how many minutes will it take for him to finish
  
 
<math> \mathrm{(A) \ 4 } \qquad \mathrm{(B) \ 6 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 10 } \qquad \mathrm{(E) \ 12 }  </math>
 
<math> \mathrm{(A) \ 4 } \qquad \mathrm{(B) \ 6 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 10 } \qquad \mathrm{(E) \ 12 }  </math>
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It will take him <math>300\cdot2=600</math> seconds to paint all the dimples.  
 
It will take him <math>300\cdot2=600</math> seconds to paint all the dimples.  
  
This is equivilant to <math>\frac{600}{60}=10</math> minutes <math>\Rightarrow D</math>.  
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This is equivalent to <math>\frac{600}{60}=10</math> minutes <math>\Rightarrow \boxed{D}</math>.
  
 
==See Also==
 
==See Also==
{{AMC8 box|year=2001|num-b=First Question|num-a=2}}
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{{AMC8 box|year=2001 |before=First<br />Question|num-a=2}}
  
 
[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Latest revision as of 12:33, 31 July 2024

Problem

Casey's shop class is making a golf trophy. He has to paint 300 dimples on a golf ball. If it takes him 2 seconds to paint one dimple, how many minutes will it take for him to finish

$\mathrm{(A) \ 4 } \qquad \mathrm{(B) \ 6 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 10 } \qquad \mathrm{(E) \ 12 }$

Solution

It will take him $300\cdot2=600$ seconds to paint all the dimples.

This is equivalent to $\frac{600}{60}=10$ minutes $\Rightarrow \boxed{D}$.

See Also

2001 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
First
Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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