Difference between revisions of "2001 AMC 8 Problems/Problem 13"

(Created page with '==Problem== Of the 36 students in Richelle's class, 12 prefer chocolate pie, 8 prefer apple, and 6 prefer blueberry. Half of the remaining students prefer cherry pie and half pr…')
 
(Video Solution 1)
 
(5 intermediate revisions by 4 users not shown)
Line 4: Line 4:
  
 
<math>\text{(A)}\ 10 \qquad \text{(B)}\ 20 \qquad \text{(C)}\ 30 \qquad \text{(D)}\ 50 \qquad \text{(E)}\ 72</math>
 
<math>\text{(A)}\ 10 \qquad \text{(B)}\ 20 \qquad \text{(C)}\ 30 \qquad \text{(D)}\ 50 \qquad \text{(E)}\ 72</math>
 
  
 
==Solution==
 
==Solution==
  
 
There are <math> 36 </math> students in the class: <math> 12 </math> prefer chocolate pie, <math> 8 </math> prefer apple pie, and <math> 6 </math> prefer blueberry pie. Therefore, <math> 36-12-8-6=10 </math> students prefer cherry pie or lemon pie. Half of these prefer each, so <math> 5 </math> students prefer cherry pie. This means that <math> \frac{5}{36} </math> of the students prefer cherry pie, so <math> \frac{5}{36} </math> of the full <math> 360^\circ </math> should be used for cherry pie. This is <math> (\frac{5}{36})(360^\circ)=50^\circ, \boxed{\text{D}} </math>
 
There are <math> 36 </math> students in the class: <math> 12 </math> prefer chocolate pie, <math> 8 </math> prefer apple pie, and <math> 6 </math> prefer blueberry pie. Therefore, <math> 36-12-8-6=10 </math> students prefer cherry pie or lemon pie. Half of these prefer each, so <math> 5 </math> students prefer cherry pie. This means that <math> \frac{5}{36} </math> of the students prefer cherry pie, so <math> \frac{5}{36} </math> of the full <math> 360^\circ </math> should be used for cherry pie. This is <math> (\frac{5}{36})(360^\circ)=50^\circ, \boxed{\text{D}} </math>
 +
 +
==Video Solution==
 +
https://youtu.be/4dhUeOdXvUk
 +
Soo, DRMS, NM
  
 
==See Also==
 
==See Also==
{{AMC8 box|year=2001|num-b=11|num-a=13}}
+
{{AMC8 box|year=2001|num-b=12|num-a=14}}
 +
{{MAA Notice}}

Latest revision as of 23:50, 19 February 2022

Problem

Of the 36 students in Richelle's class, 12 prefer chocolate pie, 8 prefer apple, and 6 prefer blueberry. Half of the remaining students prefer cherry pie and half prefer lemon. For Richelle's pie graph showing this data, how many degrees should she use for cherry pie?

$\text{(A)}\ 10 \qquad \text{(B)}\ 20 \qquad \text{(C)}\ 30 \qquad \text{(D)}\ 50 \qquad \text{(E)}\ 72$

Solution

There are $36$ students in the class: $12$ prefer chocolate pie, $8$ prefer apple pie, and $6$ prefer blueberry pie. Therefore, $36-12-8-6=10$ students prefer cherry pie or lemon pie. Half of these prefer each, so $5$ students prefer cherry pie. This means that $\frac{5}{36}$ of the students prefer cherry pie, so $\frac{5}{36}$ of the full $360^\circ$ should be used for cherry pie. This is $(\frac{5}{36})(360^\circ)=50^\circ, \boxed{\text{D}}$

Video Solution

https://youtu.be/4dhUeOdXvUk Soo, DRMS, NM

See Also

2001 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png