Difference between revisions of "2011 AMC 12B Problems/Problem 2"
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Josanna's test scores to date are <math>90, 80, 70, 60,</math> and <math>85.</math> Her goal is to raise her test average at least <math>3</math> points with her next test. What is the minimum test score she would need to accomplish this goal? | Josanna's test scores to date are <math>90, 80, 70, 60,</math> and <math>85.</math> Her goal is to raise her test average at least <math>3</math> points with her next test. What is the minimum test score she would need to accomplish this goal? | ||
− | <math> | + | <math>\textbf{(A)}\ 80 \qquad |
− | \textbf{(A)}\ 80 \qquad | ||
\textbf{(B)}\ 82 \qquad | \textbf{(B)}\ 82 \qquad | ||
\textbf{(C)}\ 85 \qquad | \textbf{(C)}\ 85 \qquad | ||
\textbf{(D)}\ 90 \qquad | \textbf{(D)}\ 90 \qquad | ||
\textbf{(E)}\ 95 </math> | \textbf{(E)}\ 95 </math> | ||
− | |||
== Solution == | == Solution == | ||
Line 20: | Line 18: | ||
<cmath> 385+x = 480 </cmath> | <cmath> 385+x = 480 </cmath> | ||
− | <cmath> x = \boxed{95 | + | <cmath> x = \boxed{95 \textbf{(E)}} </cmath> |
== See also == | == See also == | ||
{{AMC12 box|year=2011|num-b=1|num-a=3|ab=B}} | {{AMC12 box|year=2011|num-b=1|num-a=3|ab=B}} | ||
+ | |||
+ | [[Category:Introductory Algebra Problems]] | ||
+ | {{MAA Notice}} |
Latest revision as of 14:12, 19 January 2021
Problem
Josanna's test scores to date are and
Her goal is to raise her test average at least
points with her next test. What is the minimum test score she would need to accomplish this goal?
Solution
Take the average of her current test scores, which is
This means that she wants her test average after the sixth test to be Let
be the score that Josanna receives on her sixth test. Thus, our equation is
See also
2011 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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