Difference between revisions of "1998 AJHSME Problems/Problem 1"
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For <math>x=7</math>, which of the following is the smallest? | For <math>x=7</math>, which of the following is the smallest? | ||
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<math>\text{(A)}\ \dfrac{6}{x} \qquad \text{(B)}\ \dfrac{6}{x+1} \qquad \text{(C)}\ \dfrac{6}{x-1} \qquad \text{(D)}\ \dfrac{x}{6} \qquad \text{(E)}\ \dfrac{x+1}{6}</math> | <math>\text{(A)}\ \dfrac{6}{x} \qquad \text{(B)}\ \dfrac{6}{x+1} \qquad \text{(C)}\ \dfrac{6}{x-1} \qquad \text{(D)}\ \dfrac{x}{6} \qquad \text{(E)}\ \dfrac{x+1}{6}</math> | ||
− | ==Solution | + | ==Solution== |
− | + | ===Solution 1=== | |
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− | ==Solution | ||
Plugging <math>x</math> in for every answer choice would give | Plugging <math>x</math> in for every answer choice would give | ||
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== See also == | == See also == | ||
− | {{AJHSME box|year=1998|before= | + | {{AJHSME box|year=1998|before=First question|num-a=2}} |
* [[AJHSME]] | * [[AJHSME]] | ||
* [[AJHSME Problems and Solutions]] | * [[AJHSME Problems and Solutions]] | ||
* [[Mathematics competition resources]] | * [[Mathematics competition resources]] | ||
+ | {{MAA Notice}} |
Latest revision as of 16:27, 25 November 2022
Contents
Problem
For , which of the following is the smallest?
Solution
Solution 1
Plugging in for every answer choice would give
From here, we can see that the smallest is answer choice
See also
1998 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by First question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.