Difference between revisions of "2003 AMC 8 Problems/Problem 1"
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==Problem 1== | ==Problem 1== | ||
| − | Jamie counted the number of edges of a cube, Jimmy counted the numbers of corners, and Judy counted the number of faces. They then added the three numbers. What was the resulting sum? | + | Jamie counted the number of edges of a cube, Jimmy counted the numbers of corners, and Judy counted the number of faces. They then added the three numbers. What was the resulting sum? |
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==Solution== | ==Solution== | ||
On a cube, there are <math> 12 </math> edges, <math> 8 </math> corners, and <math> 6 </math> faces. Adding them up gets <math> 12+8+6= \boxed{\mathrm{(E)}\ 26} </math>. | On a cube, there are <math> 12 </math> edges, <math> 8 </math> corners, and <math> 6 </math> faces. Adding them up gets <math> 12+8+6= \boxed{\mathrm{(E)}\ 26} </math>. | ||
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| + | ==See Also== | ||
| + | {{AMC8 box|year=2003|before=First <br />Question|num-a=2}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 15:42, 19 August 2024
Problem 1
Jamie counted the number of edges of a cube, Jimmy counted the numbers of corners, and Judy counted the number of faces. They then added the three numbers. What was the resulting sum?
Solution
On a cube, there are 
edges, 
corners, and 
faces. Adding them up gets 
.
See Also
| 2003 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
