Difference between revisions of "2012 AMC 10B Problems/Problem 5"
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| − | == | + | == Solution == |
| − | Let | + | Let <math>x</math> be the cost of her dinner. |
| − | <math>27.50= | + | <math>27.50=x+\frac{1}{10}*x+\frac{3}{20}*x</math> |
| − | <math>27+\frac{1}{2}=\frac{5}{4}* | + | <math>27+\frac{1}{2}=\frac{5}{4}*x</math> |
| − | <math>\frac{55}{2}=\frac{5}{4} | + | <math>\frac{55}{2}=\frac{5}{4}x</math> |
| − | <math>\frac{55}{2}*\frac{4}{5}= | + | <math>\frac{55}{2}*\frac{4}{5}=x</math> |
| − | <math> | + | <math>x=22</math> |
| − | + | <math>\boxed{\textbf{(D)}}</math> | |
| − | |||
| − | <math> \textbf{(D)}</math> | ||
==See Also== | ==See Also== | ||
Latest revision as of 14:02, 1 May 2021
Problem 5
Anna enjoys dinner at a restaurant in Washington, D.C., where the sales tax on meals is 10%. She leaves a 15% tip on the price of her meal before the sales tax is added, and the tax is calculated on the pre-tip amount. She spends a total of 27.50 dollars for dinner. What is the cost of her dinner without tax or tip in dollars?
Solution
Let 
be the cost of her dinner.
See Also
| 2012 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
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