Difference between revisions of "1968 AHSME Problems/Problem 8"
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== Solution == | == Solution == | ||
| − | <math>\fbox{B}</math> | + | |
| + | Let <math>n</math> be the original number in question. The number divided by 6 is <math>\frac{n}{6}</math>, and the number multiplied by 6 is <math>6n</math>. Because <math>\frac{n}{6}=\frac{1}{36}*6n</math>, and <math>\frac{1}{36}=0.02 \overline{7} \approx 0.03=3</math>%, the error (which is our deviation from the correct value) is about <math>97</math>%. Thus, our answer is <math>\fbox{B}</math>. | ||
== See also == | == See also == | ||
| − | {{AHSME box|year=1968|num-b=7|num-a=9}} | + | {{AHSME 35p box|year=1968|num-b=7|num-a=9}} |
[[Category: Introductory Algebra Problems]] | [[Category: Introductory Algebra Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 18:22, 17 July 2024
Problem
A positive number is mistakenly divided by 
instead of being multiplied by 
Based on the correct answer, the error thus committed, to the nearest percent, is :
Solution
Let 
be the original number in question. The number divided by 6 is 
, and the number multiplied by 6 is 
. Because 
, and 
%, the error (which is our deviation from the correct value) is about 
%. Thus, our answer is 
.
See also
| 1968 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
