Difference between revisions of "1956 AHSME Problems/Problem 1"
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− | == | + | ==Problem #1== |
− | The value of <math>x + x(x^x)</math> when <math>x = 2</math> is: | + | The value of <math>x + x(x^x)</math> when <math>x = 2</math> is: |
− | <math>(A) 10 | + | |
+ | <math>\textbf{(A)}\ 10 \qquad\textbf{(B)}\ 16 \qquad\textbf{(C)}\ 18 \qquad\textbf{(D)}\ 36 \qquad\textbf{(E)}\ 64 </math> | ||
== Solution == | == Solution == | ||
+ | |||
+ | Simple substitution yields | ||
+ | <cmath>2 + 2(2^2) = 2 + 2(4) = 10</cmath> | ||
+ | |||
+ | Therefore, the answer is <math>\fbox{(A) 10}</math> | ||
+ | |||
+ | |||
+ | ==See Also== | ||
+ | |||
+ | {{AHSME 50p box|year=1956|before=First Problem|num-a=2}} | ||
+ | |||
+ | {{MAA Notice}} |
Latest revision as of 16:54, 14 March 2023
Problem #1
The value of when
is:
Solution
Simple substitution yields
Therefore, the answer is
See Also
1956 AHSC (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
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