Difference between revisions of "1956 AHSME Problems/Problem 1"
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| − | == | + | ==Problem #1== |
The value of <math>x + x(x^x)</math> when <math>x = 2</math> is: | The value of <math>x + x(x^x)</math> when <math>x = 2</math> is: | ||
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<math>\textbf{(A)}\ 10 \qquad\textbf{(B)}\ 16 \qquad\textbf{(C)}\ 18 \qquad\textbf{(D)}\ 36 \qquad\textbf{(E)}\ 64 </math> | <math>\textbf{(A)}\ 10 \qquad\textbf{(B)}\ 16 \qquad\textbf{(C)}\ 18 \qquad\textbf{(D)}\ 36 \qquad\textbf{(E)}\ 64 </math> | ||
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Therefore, the answer is <math>\fbox{(A) 10}</math> | Therefore, the answer is <math>\fbox{(A) 10}</math> | ||
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==See Also== | ==See Also== | ||
| − | {{AHSME box|year=1956|before= | + | {{AHSME 50p box|year=1956|before=First Problem|num-a=2}} |
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{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 15:54, 14 March 2023
Problem #1
The value of 
when 
is:
Solution
Simple substitution yields
![\[2 + 2(2^2) = 2 + 2(4) = 10\]](http://latex.artofproblemsolving.com/8/3/f/83f3051ce6110cecd8c706dbc393ac683b6f13f7.png)
Therefore, the answer is 
See Also
| 1956 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
