Difference between revisions of "1979 AHSME Problems/Problem 29"
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== See also == | == See also == | ||
− | {{AHSME box|year=1979| | + | {{AHSME box|year=1979|num-b=28|num-a=30}} |
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] |
Latest revision as of 20:25, 2 October 2018
Problem
For each positive number , let
.
The minimum value of
is
Solution
Let and
. Then
By difference of squares,
By the AM-GM inequality,
so
. Furthermore, when
,
, so the minimum value of
is
.
See also
1979 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 28 |
Followed by Problem 30 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |