Difference between revisions of "2017 AMC 10A Problems/Problem 2"
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==Problem== | ==Problem== | ||
− | Pablo buys popsicles for his friends. The store sells single popsicles for \$1 each, 3-popsicle boxes for \$2 each, and 5-popsicle boxes for \$3. What is the greatest number of popsicles that Pablo can buy with \$8? | + | Pablo buys popsicles for his friends. The store sells single popsicles for <math>\$1</math> each, <math>3</math>-popsicle boxes for <math>\$2</math> each, and <math>5</math>-popsicle boxes for <math>\$3</math>. What is the greatest number of popsicles that Pablo can buy with <math>\$8</math>? |
<math>\textbf{(A)}\ 8\qquad\textbf{(B)}\ 11\qquad\textbf{(C)}\ 12\qquad\textbf{(D)}\ 13\qquad\textbf{(E)}\ 15</math> | <math>\textbf{(A)}\ 8\qquad\textbf{(B)}\ 11\qquad\textbf{(C)}\ 12\qquad\textbf{(D)}\ 13\qquad\textbf{(E)}\ 15</math> | ||
+ | |||
+ | ==Solution== | ||
+ | |||
+ | <math>\$3</math> boxes give us the most popsicles/dollar, so we want to buy as many of those as possible. After buying <math>2</math>, we have <math>\$2</math> left. We cannot buy a third <math>\$3</math> box, so we opt for the <math>\$2</math> box instead (since it has a higher popsicles/dollar ratio than the <math>\$1</math> pack). We're now out of money. We bought <math>5+5+3=13</math> popsicles, so the answer is <math>\boxed{\textbf{(D) }13}</math>. | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/str7kmcRMY8 | ||
+ | |||
+ | https://youtu.be/9VGPpemq-qg | ||
+ | |||
+ | ~savannahsolver | ||
+ | |||
+ | ==See Also== | ||
+ | {{AMC10 box|year=2017|ab=A|num-b=1|num-a=3}} | ||
+ | {{MAA Notice}} |
Latest revision as of 17:10, 16 June 2020
Contents
Problem
Pablo buys popsicles for his friends. The store sells single popsicles for each,
-popsicle boxes for
each, and
-popsicle boxes for
. What is the greatest number of popsicles that Pablo can buy with
?
Solution
boxes give us the most popsicles/dollar, so we want to buy as many of those as possible. After buying
, we have
left. We cannot buy a third
box, so we opt for the
box instead (since it has a higher popsicles/dollar ratio than the
pack). We're now out of money. We bought
popsicles, so the answer is
.
Video Solution
~savannahsolver
See Also
2017 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.