Difference between revisions of "2014 AMC 8 Problems/Problem 1"
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==Problem== | ==Problem== | ||
− | Harry and Terry are each told to calculate <math>8-(2+5)</math>. Harry gets the correct answer. Terry ignores the parentheses and calculates <math>8-2+5</math>. If | + | Harry and Terry are each told to calculate <math>8-(2+5)</math>. Harry gets the correct answer. Terry ignores the parentheses and calculates <math>8-2+5</math>. If Harry's answer is <math>H</math> and Terry's answer is <math>T</math>, what is <math>H-T</math>? |
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<math>\textbf{(A) }-10\qquad\textbf{(B) }-6\qquad\textbf{(C) }0\qquad\textbf{(D) }6\qquad \textbf{(E) }10</math> | <math>\textbf{(A) }-10\qquad\textbf{(B) }-6\qquad\textbf{(C) }0\qquad\textbf{(D) }6\qquad \textbf{(E) }10</math> | ||
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We have <math>H=8-7=1</math> and <math>T=8-2+5=11</math>. Clearly <math>1-11=-10</math> | We have <math>H=8-7=1</math> and <math>T=8-2+5=11</math>. Clearly <math>1-11=-10</math> | ||
, so our answer is <math>\boxed{\textbf{(A)}-10}</math>. | , so our answer is <math>\boxed{\textbf{(A)}-10}</math>. | ||
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+ | ==Video Solution (CREATIVE THINKING)== | ||
+ | https://youtu.be/dljBE3_G85E | ||
+ | |||
+ | ~Education, the Study of Everything | ||
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+ | |||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/6TRHPxBveh0 | ||
+ | |||
+ | ~savannahsolver | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2014|before=First Problem|num-a=2}} | {{AMC8 box|year=2014|before=First Problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 11:18, 2 July 2023
Problem
Harry and Terry are each told to calculate . Harry gets the correct answer. Terry ignores the parentheses and calculates
. If Harry's answer is
and Terry's answer is
, what is
?
Solution
We have and
. Clearly
, so our answer is
.
Video Solution (CREATIVE THINKING)
~Education, the Study of Everything
Video Solution
~savannahsolver
See Also
2014 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.