Difference between revisions of "2020 AMC 10A Problems/Problem 4"
Mathsmiley (talk | contribs) (→Solution: Added a Solution) |
m |
||
| Line 9: | Line 9: | ||
==Solution== | ==Solution== | ||
Since the driver travels 60 miles per hour and each hour she uses 2 gallons of gasoline, she spends \$4 per hour on gas. If she gets \$0.50 per mile, then she gets \$30 per hour of driving. Subtracting the gas cost, her net rate of pay per hour is <math>\boxed{\textbf{(E)}\ 26}</math>. | Since the driver travels 60 miles per hour and each hour she uses 2 gallons of gasoline, she spends \$4 per hour on gas. If she gets \$0.50 per mile, then she gets \$30 per hour of driving. Subtracting the gas cost, her net rate of pay per hour is <math>\boxed{\textbf{(E)}\ 26}</math>. | ||
| + | |||
| + | ==Video Solution== | ||
| + | https://youtu.be/WUcbVNy2uv0 | ||
| + | |||
| + | ~IceMatrix | ||
==See Also== | ==See Also== | ||
Revision as of 22:09, 31 January 2020
- The following problem is from both the 2020 AMC 12A #3 and 2020 AMC 10A #4, so both problems redirect to this page.
Contents
Problem 4
A driver travels for 
hours at 
miles per hour, during which her car gets 
miles per gallon of gasoline. She is paid 
per mile, and her only expense is gasoline at 
per gallon. What is her net rate of pay, in dollars per hour, after this expense?
Solution
Since the driver travels 60 miles per hour and each hour she uses 2 gallons of gasoline, she spends $4 per hour on gas. If she gets $0.50 per mile, then she gets $30 per hour of driving. Subtracting the gas cost, her net rate of pay per hour is 
.
Video Solution
~IceMatrix
See Also
| 2020 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
