Difference between revisions of "2020 AMC 10A Problems/Problem 11"
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+ | ~IceMatrix | ||
==See Also== | ==See Also== |
Revision as of 23:15, 31 January 2020
- The following problem is from both the 2020 AMC 12A #8 and 2020 AMC 10A #11, so both problems redirect to this page.
Contents
Problem 11
What is the median of the following list of numbers
Solution
We can see that is less than 2020. Therefore, there are
of the
numbers after
. Also, there are
numbers that are under and equal to
. Since
is
it, with the other squares will shift our median's placement up
. We can find that the median of the whole set is
, and
gives us
. Our answer is
.
~aryam
Video Solution
~IceMatrix
See Also
2020 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.