Difference between revisions of "1990 AIME Problems/Problem 11"
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== Problem == | == Problem == | ||
| + | Someone observed that <math>6! = 8 \cdot 9 \cdot 10</math>. Find the largest positive integer <math>n^{}_{}</math> for which <math>n^{}_{}!</math> can be expressed as the product of <math>n - 3_{}^{}</math> consecutive positive integers. | ||
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== Solution == | == Solution == | ||
{{solution}} | {{solution}} | ||
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== See also == | == See also == | ||
| − | + | {{AIME box|year=1990|num-b=10|num-a=12}} | |
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Revision as of 00:34, 2 March 2007
Problem
Someone observed that 
. Find the largest positive integer 
for which 
can be expressed as the product of 
consecutive positive integers.
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See also
| 1990 AIME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 10 |
Followed by Problem 12 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
