Difference between revisions of "2016 AMC 10A Problems/Problem 16"
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==Solution== | ==Solution== | ||
Consider a point <math>(x, y)</math>. Reflecting it about the <math>x</math>-axis will map it to <math>(x, -y)</math>, and rotating it counterclockwise about the origin by <math>90^{\circ}</math> will map it to <math>(y, x)</math>. The operation that undoes this is a reflection about the <math>y = x</math>, so the answer is <math>\boxed{\textbf{(D)}}</math>. | Consider a point <math>(x, y)</math>. Reflecting it about the <math>x</math>-axis will map it to <math>(x, -y)</math>, and rotating it counterclockwise about the origin by <math>90^{\circ}</math> will map it to <math>(y, x)</math>. The operation that undoes this is a reflection about the <math>y = x</math>, so the answer is <math>\boxed{\textbf{(D)}}</math>. | ||
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+ | ==Video Solution (CREATIVE THINKING)== | ||
+ | https://youtu.be/xUJao7B5BHw | ||
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+ | ~Education, the Study of Everything | ||
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==Video Solution== | ==Video Solution== |
Latest revision as of 13:52, 25 June 2023
Contents
Problem
A triangle with vertices , , and is reflected about the -axis, then the image is rotated counterclockwise about the origin by to produce . Which of the following transformations will return to ?
counterclockwise rotation about the origin by .
clockwise rotation about the origin by .
reflection about the -axis
reflection about the line
reflection about the -axis.
Solution
Consider a point . Reflecting it about the -axis will map it to , and rotating it counterclockwise about the origin by will map it to . The operation that undoes this is a reflection about the , so the answer is .
Video Solution (CREATIVE THINKING)
~Education, the Study of Everything
Video Solution
https://www.youtube.com/watch?v=VHXDQz5BG8U
Video Solution 2
~IceMatrix
See Also
2016 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 15 |
Followed by Problem 17 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.