Difference between revisions of "2016 AMC 10A Problems/Problem 14"
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==See Also== | ==See Also== | ||
{{AMC10 box|year=2016|ab=A|num-b=13|num-a=15}} | {{AMC10 box|year=2016|ab=A|num-b=13|num-a=15}} | ||
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Revision as of 15:09, 4 December 2020
Problem
How many ways are there to write as the sum of twos and threes, ignoring order? (For example,
and
are two such ways.)
Solution 1
The amount of twos in our sum ranges from to
, with differences of
because
.
The possible amount of twos is .
Solution 2
You can also see that you can rewrite the word problem into an equation +
=
. Therefore the question is just how many multiples of
subtracted from 2016 will be an even number. We can see that
,
all the way to
, and
works, with
being incremented by
's.Therefore, between
and
, the number of multiples of
is
.
Solution 3
We can utilize the stars-and-bars distribution technique to solve this problem.
We have 2 "buckets" in which we will distribute parts of our total sum, 2016. By doing this, we know we will have "total" answers. We want every third x and second y, so we divide our previous total by 6, which will result in
. We have to round down to the nearest integer, and we have to add 2 because we did not consider the 2 solutions involving x or y being 0.
So,
.
Video Solution
https://youtu.be/dHY8gjoYFXU?t=1058
~IceMatrix
~savannahsolver
See Also
2016 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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