Difference between revisions of "2020 AMC 8 Problems/Problem 15"
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==Solution 1== | ==Solution 1== | ||
We set up the following equation based on the given information: <cmath>\frac{15x}{100}=\frac{20y}{100}</cmath> Solving for <math>x</math> yields <cmath>\frac{3x}{20}=\frac{y}{5}</cmath> <cmath>20y=15x</cmath> <cmath>x=1.\overline{3}y ==> D</cmath> | We set up the following equation based on the given information: <cmath>\frac{15x}{100}=\frac{20y}{100}</cmath> Solving for <math>x</math> yields <cmath>\frac{3x}{20}=\frac{y}{5}</cmath> <cmath>20y=15x</cmath> <cmath>x=1.\overline{3}y ==> D</cmath> | ||
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+ | ==See also== | ||
+ | {{AMC8 box|year=2020|num-b=14|num-a=16}} | ||
+ | {{MAA Notice}} |
Revision as of 00:21, 18 November 2020
Problem 15
Suppose of equals of What percentage of is
Solution 1
We set up the following equation based on the given information: Solving for yields
See also
2020 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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